A small rock moves in water, and the force exerted on it by the water is given by the equation Fd = kv, where k is a constant. The terminal speed of the rock is measured and found to be 2.0m/s. The rock is projected upward at an initial speed of 6.0m/s. You can ignore the buoyancy force on the rock. Find the maximum height that the rock reaches.

asked by Timothy

13 years ago

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1 answer

Vf^2 = Vo^2 + 2g*d,
d = (Vf^2 - Vo^2) / 2g,
d = (2^2 - 6^2) / -19.6 = 1.63m.

answered by Henry

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3

Question

A small rock moves in water, and the force exerted on it by the water is given by the equation Fd = kv, where k is a constant. The terminal speed of the rock is measured and found to be 2.0m/s. The rock is projected upward at an initial speed of 6.0m/s. You can ignore the buoyancy force on the rock. Find the maximum height that the rock reaches.

1 answer

Vf^2 = Vo^2 + 2g*d,
d = (Vf^2 - Vo^2) / 2g,
d = (2^2 - 6^2) / -19.6 = 1.63m.

Henry · Answer

Vf^2 = Vo^2 + 2g*d, d = (Vf^2 - Vo^2) / 2g, d = (2^2 - 6^2) / -19.6 = 1.63m.