If the car stops in t seconds, the deceleration a is 35.5/t
The distance traveled is
s(t) = 35.5t - (35.5/2t)t^2 = 52.7
so, t = 2.97 seconds.
a = 35.5/2.97 = 11.953 m/s^2
F = ma = 2165.7 * 11.953 = 25,886 N
A(n) 2165.7 kg car is coasting along a level
road at 35.5 m/s. A constant braking force
is applied, such that the car is stopped in a
distance of 52.7 m.
What is the magnitude of the braking force?
Answer in units of N.
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