I used the same Eq and procedure you
used and I got 25899.9N. So, i agree with your answer.
A 2172.5 kg car is coasting along a level road at 34.7 m/s.
A constant braking force is applied,such that the car is stopped in a distance of 50.5 m.
What is the magnitude of the braking force? Answer in N.
Here is my way, but im not sure if im correct:
Vf^2=Vi^2+2a(delta position)
0=34.7^2+2a(50.5)
=11.92 m/s^2
2172.5(11.92)=25,896.2 N
2 answers
thanks!!