A(n) 1949.1 kg car is coasting along a level road at 22.9 m/s. A constant braking force is applied, such that the car is stopped in a distance of 74.6 m.

Question

What is the magnitude of the braking force? Answer in units of N

Answer 1

a = (V^2-Vo^2)/2d = (0-(22.9^2)/149.2 =
-3.51 m/s^2.

F = m*a =1949.1 * (-3.51) = -6851 N.

Note: The negative sign means that the
force opposes the motion.