A motorist drives north for 35.0 s at 25.0 m/s and then stops for 23.0 s. He then continues north traveling 13.0 m in 2.00 s. (a) What is his total displacement? (b) What is his average velocity (magnitude and direction)?
I am just clueless on this one. I don't even know where to start. The stopping for "23 s and resuming" really confuses me. Pls help.
What are your given equations? If you don't know, google for them.
d – the displacement of the object.
t – the time for which the object moved.
a – the acceleration of the object.
vi – the initial velocity of the object.
vf – the final velocity of the object.
Displacement the object's change in position. So a is asking you to calculate the object's change in position.
Since he has two different velocities, you must calculate two different displacements and add them together.
For the first velocity: time = 35seconds velocity = 25 m/s.
I think the 23 seconds of stopping is intentionally included to confuse you. It doesn't matter to the overall calculation because not moving doesn't influence your displacement calculation.
Thank you Ann!
I had the equations and really was closing in on the answer... (stopping for 23 s is what really got me confused) in either case, the displacement for a) is 888 m !
Now I'll try to calculate (b).
Thank you much!
correct, it just affects the total time.
averagevelocity= displacement/totaltime
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