A salesperson leaves the office and drives 26 km north along a straight highway. A turn is made onto a highway that leads in a direction of 60 degrees. The driver continues on the highway for a distance of 62 km and then stops. What is the total displacement of the salesperson from the office?

Answer 1

D = 26km[90o] + 62km[60o].

X = 62*Cos60 = 31km.
Y = 26 + 62*sin60 = 79.7 km.
Q1.

Tan A = Y/X = 79.7/31 = 2.57076.
A = 68.7o = Direction.

D = Y/sin A = 79.7/sin68.7 = 85.5 km[68.7o].