A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle are both traveling at the same speed of 21.5 m/s , and the distance between them is 57.0 m . After t1 = 3.00 s , the motorcycle starts to accelerate at a rate of 8.00 m/s2 . The motorcycle catches up with the car at some time t2.

1 answer

They start out at the same speed so we are just on a surface moving at 21.5 m/s
All the motorcycle has to do is cover the difference, 57 meters
d = (1/2) a t^2
57 = (1/2) 8 * t^2
t^2 = 57/4 seconds to catch up (about 14 seconds). t2= t1 + t
the car travels 21.5 ( 3 + t) meters
and the motorcycle covers 57 meters more.