A motorcycle daredevil is attempting to jump across as many buses as possible (see the drawing). The takeoff ramp makes an angle θ = 16.8° above the horizontal, and the landing ramp is identical to the takeoff ramp. The buses are parked side by side, and each bus is 2.74 m wide. The cyclist leaves the ramp with a speed of v = 33.0 m/s. What is the maximum number of buses over which the cyclist can jump?

Question

What I try to do is find the vertical and horizontal velocities independently. Then I find the time using the vertical velocity by setting up Vf=Vi+at and I make Vf just the negative of the Vi. Then I take the time I found and try delta(x)= Vavg (which is the same throughout) x time. With this value, I divide it by the distance of the buses. What should I fix??

Answer 1

Dx = Vo^2*sin(2A)/g = 33^2*sin33.6/9.8 =
65.13 m.

65.13m/2.74 = 23.8 or 23 Busses.