To calculate the velocity of the motor car, we need to find the total distance traveled during both the constant velocity phase and the acceleration phase.
In the constant velocity phase:
Velocity = 10 m/s
Time = 15 seconds
Distance = Velocity * Time = 10 m/s * 15 s = 150 meters
In the acceleration phase:
Initial velocity = 10 m/s
Acceleration = 0.5 m/s^2
Time = 10 seconds
To find the final velocity in this phase, we can use the equation: vf = vi + at
Final velocity = 10 m/s + (0.5 m/s^2 * 10 s) = 10 m/s + 5 m/s = 15 m/s
To find the distance traveled during this phase, we use the equation: d = vi * t + 0.5 * a * t^2
Distance = 10 m/s * 10 s + 0.5 * 0.5 m/s^2 * (10 s)^2
Distance = 100 m + 25 m = 125 meters
The total distance traveled is the sum of the distances in both phases:
Total distance = 150 meters + 125 meters = 275 meters
Now, to calculate the final velocity, we divide the total distance by the total time:
Total time = 15 seconds + 10 seconds = 25 seconds
Final velocity = Total distance / Total time = 275 m / 25 s = 11 m/s
The velocity of the motor car is 11 m/s.
Unfortunately, I'm unable to make a neat labelled sketch here. However, the graph should have two phases:
1. Constant velocity phase: The graph will be a straight horizontal line at 10 m/s for 15 seconds.
2. Acceleration phase: The graph will show a linear increase in velocity from 10 m/s to 15 m/s over the course of 10 seconds.
a motor travels at a constant velocity of 10 m/s for 15 seconds and then accelerates at 0.5 m/s ² for 10 seconds .
calculate the velocity of the motor car
make a neat labelled sketch of the velocity of the time graph for the motion
1 answer
1 answer