Asked by michelle
A car travels at a constant speed of 30 mph for 20 miles, at a speed of 40 fps for the next 20 miles, and then travels the final 20 miles at 90 kph. what is the average speed of the entire trip?
Answers
Answered by
Henry
d1 = V1*t1
t1 = d1/V1 = 20/30 = 0.667 h.
V2=40Ft/s * 1m1/5280Ft * 3600s/h = 27.3 mi/h.
t2 = d2/V2 = 20/27.3 = 0.733 h.
V3 = 90km/h * 1m1/1.6km = 56.3 mi/h.
t3 = d3/V3 = 20/56.3 = 0.355 h.
d = d1+d2+d3 = 20 + 20 + 20 = 60 mi.
T = t1+t2+t3 = 0.667 + 0.733 + 0.355 =
1.76 h.
V = d/T = 60mi/1.76h = 34.1 mi/h.
t1 = d1/V1 = 20/30 = 0.667 h.
V2=40Ft/s * 1m1/5280Ft * 3600s/h = 27.3 mi/h.
t2 = d2/V2 = 20/27.3 = 0.733 h.
V3 = 90km/h * 1m1/1.6km = 56.3 mi/h.
t3 = d3/V3 = 20/56.3 = 0.355 h.
d = d1+d2+d3 = 20 + 20 + 20 = 60 mi.
T = t1+t2+t3 = 0.667 + 0.733 + 0.355 =
1.76 h.
V = d/T = 60mi/1.76h = 34.1 mi/h.
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