A model airplane 50 feet above the ground is flying away from an observer. Find the angle of elevation theta of the plane as a function of the distance from the observer to the plane. What is theta when the plane is 300 feet from the observer?

Answer 1

sin theta = 50/d
if d = 300

sin theta = 50/300 = 1/6

theta = 9.6 degrees

Answer 2

If I drew a triangle the d would be the hypotenuse?