Asked by Emily
A mixture of argon and hydrogen gases contains argon at a partial pressure of 241 mm Hg and hydrogen at a partial pressure of 534 mm Hg. What is the mole fraction of each gas in the mixture?
Answers
Answered by
DrBob222
A mixture of argon and hydrogen gases contains argon at a partial pressure of 241 mm Hg and hydrogen at a partial pressure of 534 mm Hg. What is the mole fraction of each gas in the mixture?
pAr = 241 mm
pH2 = 534 mm
ptotal = 241 + 534 = ?
XAr = pAr/ptotal
XH2 = pH2/ptotal
pAr = 241 mm
pH2 = 534 mm
ptotal = 241 + 534 = ?
XAr = pAr/ptotal
XH2 = pH2/ptotal
Answered by
Emily
p total is 775
Answered by
DrBob222
775 is correct for Ptotal. That will let you calculate X for Ar and X for H2.
XAr = 241/775 = ?
XH2 = 534/775 = ?
XAr = 241/775 = ?
XH2 = 534/775 = ?
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