Question

A mixture contains n2o4 and No2 in the ratio 2:1 by volume what is the vapour density of the mixture.Pls answer the question i have been on the question for 2 hrs by now tried solving using mole fraction ideal gas equation an using the formula molar mass /2 but still couldn't get the answer ans as is written is 38.3 pls tell how .explain in detail may be

Answer 1

I think the trouble you are having is knowing what vapor density is. vapor density = molar mass gas/molar mass H2.

vapor density N2O4 = molar mass N2O4/molar mass H2 = 92.011/2.016 = 45.64
vapor density NO2 = molar mass NO2/molar mass H2 = 46.0055/2.016 = 22.82

The ratio is 2:1 in favor N2O4; therefore,

v.d. N2O4 x 2 = 91.28
+ v.d. NO2 x 1 = 22.82
sum is 114.1
average is 114.1/3 = 38.033 which rounds to 38.03.

Answer 2

Molar mass of N2O4 =92
Vapour density= 46(92/2)
Molar mass of NO2=46
Vapour density=23(46/2)
Given ratio is 2:1
So vapour density of mixture is
2×46+23/3 =38.33
We devide it by 3 because
Sum of ratio is 3 .

Answer 3

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