molecules Mn2O3 = mols x 6.02E23 = ?
molecules O in Mn2O3 = 3x that
mols MnO2 = grams/molar mass = ?
molecules MnO2 = mols x 6.023E23 =?
molecules O atoms is 2x that.
Total O atoms = sum of the two.
2 is worked the same way.
A mixture contains 0.218 mol of Mn2O3 and 17.8 g of MnO2.
1.How many atoms of oxygen are present in the mixture?
2.How many grams of manganese are in the mixture?
1 answer
1 answer