...........CO + H2O ==> H2 + CO2
initial....1.....1.......0....0
change.....-x....-x.....x.....x
equil.....1-x....1-x.....x....0.647
You know x = 0.647 which allows you to calculate moles CO, H2O, H2, and CO2 at equil. Then concn = moles/L, and substitute into Keq expression to solve for Keq.
A mixture consisting of 1 mol of H2O(g) and 1 mol CO(g) is placed in a 7 L reaction vessel at 800 K. At equilibrium, 0.369 mol CO2(g)is present as a result of the reaction CO(g) + H2O(g)⇀↽CO2(g) + H2(g).What is Kc at 800 K?
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