F=Eq
q=F/E
q=2.34^-4/6620
A microscopic droplet of ink in an ink-jet printer is deflected onto the paper by a force of 2.34×10-4 N. If the field causing the deflection is 6.62 kN/C, what is the charge on the droplet?
What equation do I use to solve and What does each value mean in the equation? thnks
1 answer
1 answer