A micrometeor has a mass of 0.005 grams. When it enters Earth’s atmosphere, it travels at 21,000 meters per second. What is its kinetic energy when it enters Earth’s atmosphere?
KE=12mv2
(1 point)
Responses
0.0525 J
0.0525 J
1,102,500 J
1,102,500 J
1,102.5 J
1,102.5 J
2,205 J
2,205 J
1 answer
KE = 1/2 mv^2 = 1.2 * 5*10^-6 * 21000^2 = 1102.5
1 answer