When the tank is empty, you see 86.6 cm.
When the tank is half way full, you see 64.74 cm.
When the tank is full, you see 42.9 cm.
A meter stick lies on the bottom of a 100 cm long tank with its zero mark against the left edge. You look into the tank at an angle of θ = 30°, with your line of sight just grazing the upper left edge of the tank, and height of the tank is 50cm.
(a) What mark do you see on the meter stick if the tank is empty?
(b) What mark do you see if the tank is half full of water?
(c) What mark do you see if it is completely full of water?
3 answers
Maybe explain how tf to do the question Kastra gah damn
Yo here's how u do it since Kastra aint decide to explain this shi:
1st q simple: use tantheta=y/x, set angle as 30, and 50 cm as y.
2nd question: from the answer from the first q, divide the answer by 2. Keep it with you. Now, for the 2nd half in the water, do n1sintheta1=n2sintheta2 isolate for theta2 (make sure your using the angle as 60 degrees here, if your confused on why search up refraction in water and go to google images, this is the angle you gotta use). Then do the tan(theta)=Y/25 cm, isolate for Y. Then add this answer to the first answer/2.
3rd q: use same angle found from n1sin(theta1)=n2sin(theta2) in q2. Then just do tan(theta)=Y/50 cm, isolate for Y.
Your welcome bozo, and Kastra, you a fraud
1st q simple: use tantheta=y/x, set angle as 30, and 50 cm as y.
2nd question: from the answer from the first q, divide the answer by 2. Keep it with you. Now, for the 2nd half in the water, do n1sintheta1=n2sintheta2 isolate for theta2 (make sure your using the angle as 60 degrees here, if your confused on why search up refraction in water and go to google images, this is the angle you gotta use). Then do the tan(theta)=Y/25 cm, isolate for Y. Then add this answer to the first answer/2.
3rd q: use same angle found from n1sin(theta1)=n2sin(theta2) in q2. Then just do tan(theta)=Y/50 cm, isolate for Y.
Your welcome bozo, and Kastra, you a fraud
2 answers