since all the sticks are the same size and mass, the center is just the average of all the (x,y) midpoints:
(0,(.32+1.32)/2)
((.33+1.33)/2,0)
(.64/2,.768/2)
so, the center of mass is at
((0+(.33+1.33)/2+.64/2)/3,((.32+1.32)/2+0+.768/2)/3)
= (0.383,0.401)
Three identical uniform meter sticks are placed on the floor. The first stick lies along the y axis from y = 0.320 m to y = 1.32 m. The second stick lies along the x axis from x = 0.330 m to x = 1.33 m. The third stick is positioned so that one end is on the x axis at x = 0.640 m, and the other end is on the y axis at y = 0.768 m. Calculate the location of the center of mass of the meter sticks.
1 answer
1 answer