A metal box attached to a small parachute is dropped from helicopter

Question

A.explain in terms of the forces acting on why its velocity increased immediately after being dropped

B.why did it reach a uniform velocity after a short distance

C.the total force opposing motion of the box and the parachute at particular time during its fall is 30N.the combined mass of the box and parachute is 5kg
1. Caculate the resultant downward force and box and the parachute (g=10N)
2.briefly describe the motion of the box and parachute at this time

Answer 1

Immediately after drop its vertical speed is zero, so no drag.
therefore m a = m g and it accelerates down at 32 m/s^2
as it builds up speed and the chute deploys, the air drag increases at about proportional to speed squared until the drag force up equals the m g down and the speed becomes constant.
I already did your 30 N and g = 10 METERS/ SECOND^2 (not Newtons) question

Answer 2

Can anyone plz tell me from which book did u got this question

Answer 3

A metal box attched to a small parachute is dropped from helicopter
a) explain in term of force acting why