To compare the cost of the memberships for a year, we need to determine the cost per month for each membership.
For Gym A:
The cost for 5 months is $50.
So, the cost per month (y) at Gym A can be represented by the equation y = kx, where x is the number of months:
50 = 5k
And for Gym B:
The cost for 3 months is $40.
So, the cost per month (y) at Gym B can be represented by the equation y = kx, where x is the number of months:
40 = 3k
To find the value of k for the cheaper membership, we need to compare the two equations. Since we want to find the cheaper membership, we can compare the values of k for Gym A and Gym B.
From the equation 50 = 5k, we can solve for k by dividing both sides by 5:
50/5 = 5k/5
10 = k
From the equation 40 = 3k, we can solve for k by dividing both sides by 3:
40/3 = 3k/3
40/3 ≈ 13.333... = k
Comparing the values of k for Gym A and Gym B, we can see that k = 10 is smaller than k ≈ 13.333..., making the cost per month at Gym A (using the equation y = kx) cheaper than at Gym B. Thus, the value of k for the cheaper membership is 10.
A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership?(
3 answers
Two equations are written to express how far a car can go when driving on different roads. On Road 1, the car can go 60 miles in 2 hours. On Road 2, the car can go 90 miles in 4 hours. Write an equation where y is the distance in miles and x is the time in hours to represent the motion of the faster car.(
To represent the motion of the faster car, we need to find the equation for Road 2, where the car can go 90 miles in 4 hours.
We can express this relationship using the equation y = kx, where y is the distance in miles and x is the time in hours.
Since on Road 2, the car can go 90 miles in 4 hours, we can substitute y = 90 and x = 4 into the equation.
90 = k * 4
To find the value of k, we can solve for k by dividing both sides by 4:
90/4 = k * 4/4
22.5 = k
Therefore, the equation that represents the motion of the faster car is y = 22.5x.
We can express this relationship using the equation y = kx, where y is the distance in miles and x is the time in hours.
Since on Road 2, the car can go 90 miles in 4 hours, we can substitute y = 90 and x = 4 into the equation.
90 = k * 4
To find the value of k, we can solve for k by dividing both sides by 4:
90/4 = k * 4/4
22.5 = k
Therefore, the equation that represents the motion of the faster car is y = 22.5x.