"A mass of 45.0g of molten silver at its melting point is poured into 750mL of calorimeter water at 25.0C. The final temperature reached by both is 30.0C. If the specific heat capacity of silver is 0.235 kJ/kgC, calculate the molar heat of solidification of silver".

Question

Help! I don't know the process of solving this. Why are we given the specific heat capacity of silver?

Answer 1

heat lost by Ag turning to solid + heat lost by Ag in heating water + heat gained by water = 0

I don't think you can work this problem unless your are given the melting point of silver. You must know WHERE the initial T is. Perhaps you are to look it up. I did that on the web.
-[mass Ag x heat fusion] + [mass Ag x specific heat Ag x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
You are given all of the information except melting point of Ag AND heat fusion.

Answer 2

I don't think I need heat fusion...I'm looking for the molar heat of solidification.

But, thank you so much! I got it.

Answer 3

Just for your information, the heat of fusion and the heat of solidification are the same. Just like the heat of vaporization and heat of condensation are the same. The only difference is heat fusion is melting at the melting point and heat of solidification is the solidifying at the melting point. The equation I gave will solve for heat fusion in J/g.