Ke - work done against friction = (1/2)kx^2
(1/2)mv^2 - .3 m g (.2+x) = (1/2)(800)x^2
(1/2)*2*9 -.3*2*9.8(.2+x) = 400 x^2
solve quadratic for x
why are you talking about m g h ??? it fell on horizontal plane?
A mass of 2.0kg traveling at 3.0 m/s along a horizontal plane hits a relaxed spring 20cm away from it. The coefficient of kinetic friction is 0.3. The mass is slowed to zero velocity when the spring has been compressed. By how much the spring has been compressed, the spring constant of the spring is 800 N/m?
What I've done so far, is this right?
1/2mv^2 + mgh = 1/2mv^2 + mgh + 1/2kx^2
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