Asked by Nick
A manufacturer ship toasters in cartons of 10. In each carton, they estimate a 20% chance that one of the toasters will need to be sent back for minor repairs. What is the probability, that in one carton there will be 5 toasters that need repair?
I have no idea on where to begin to answer the question above...
I have no idea on where to begin to answer the question above...
Answers
Answered by
MathGuru
Try the binomial probability table:
n = 10
x = 5
p = .20
q = 1 - p = 1 - .20 = .80
You can use the table, or calculate by hand using the following formula:
P(x) = (nCx)(p^x)[q^(n-x)]
With your data using the formula:
P(5) = (10C5)(.20^5)[.80^(10-5)]
I'll let you take it from here.
n = 10
x = 5
p = .20
q = 1 - p = 1 - .20 = .80
You can use the table, or calculate by hand using the following formula:
P(x) = (nCx)(p^x)[q^(n-x)]
With your data using the formula:
P(5) = (10C5)(.20^5)[.80^(10-5)]
I'll let you take it from here.
Answered by
Anonymous
0.22
Answered by
troy cain
from table
0.026
0.026
Answered by
Jo
What is the C stand for
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