A manufacturer ship toasters in cartons of 10. In each carton, they estimate a 20% chance that one of the toasters will need to be sent back for minor repairs. What is the probability, that in one carton there will be 5 toasters that need repair?

Question

I have no idea on where to begin to answer the question above...

Answer 1

Try the binomial probability table:

n = 10
x = 5
p = .20
q = 1 - p = 1 - .20 = .80

You can use the table, or calculate by hand using the following formula:
P(x) = (nCx)(p^x)[q^(n-x)]

With your data using the formula:
P(5) = (10C5)(.20^5)[.80^(10-5)]

I'll let you take it from here.

Answer 2

0.22

Answer 3

from table
0.026

Answer 4

What is the C stand for