total east ... 4 m + 4 cos(60º) m
total north ... 4 sin(60º) m
A man walks 4m towards east and then turns 60degrees to his left and again walks for 4m calculate the net displacement
3 answers
D = 4m[0o] + 4m[60o].
X = 4*Cos0 + 4*Cos60 = 6 m.
Y = 4*sin 0 + 4*sin = 60 = 3.46 m.
D = sqrt(X^2 + Y^2) = 6.93 m. Displacement.
X = 4*Cos0 + 4*Cos60 = 6 m.
Y = 4*sin 0 + 4*sin = 60 = 3.46 m.
D = sqrt(X^2 + Y^2) = 6.93 m. Displacement.
6.925
1 answer