sinα=(3.92-0.506)/8.35 =0.409
α =sin⁻¹0.409 = 24.13º
F=832•cosα=832•0.913 =759.6 N
τ=759.6•3.92=2977.6 N•m
A man ties one end of a strong rope 8.35 m long to the bumper of his truck, 0.506 m from the ground, and the other end to a vertical tree trunk at a height of 3.92 m. He uses the truck to create a tension of 8.32x10^2 N in the rope. Compute the magnitude of the torque on the tree due to the tension in the rope, with the base of the tree acting as the reference point.
2 answers
where did the cos come from please
2 answers