Let's assume the man's initial salary is x.
After 12 years, we know that his total salary will be the sum of his initial salary and the increases over the 12 years.
So, the equation becomes:
x + 8000 + 8000 + 8000 +... (12 times) = 18,825,000
We can simplify this equation by realizing that the increases form an arithmetic sequence with a common difference of 8000. So, we can use the formula for the sum of an arithmetic sequence:
x + 8000(12) = 18,825,000
x + 96,000 = 18,825,000
x = 18,825,000 - 96,000
x = 18,729,000
Therefore, his initial salary is $18,729,000.
After twelve years, his salary will be his initial salary plus the total increases over the 12 years:
Salary after twelve years = 18,729,000 + 8000(12)
Salary after twelve years = 18,729,000 + 96,000
Salary after twelve years = $18,825,000.
A man salary increase by $8000.00 every year. If his total at the end of 12years is 18,825,000.00
Find his initial salary
And after twelve years
1 answer
1 answer