To determine Mr. Brown's salary for teaching 3, 4, and 5 years in the district, we can use the function \( s = 1,500y + 40,000 \).
-
For \( y = 3 \): \[ s = 1,500(3) + 40,000 = 4,500 + 40,000 = 44,500 \] So, the salary after 3 years is \( (3, 44,500) \).
-
For \( y = 4 \): \[ s = 1,500(4) + 40,000 = 6,000 + 40,000 = 46,000 \] So, the salary after 4 years is \( (4, 46,000) \).
-
For \( y = 5 \): \[ s = 1,500(5) + 40,000 = 7,500 + 40,000 = 47,500 \] So, the salary after 5 years is \( (5, 47,500) \).
Thus, the points on the graph that represent how much Mr. Brown will make for teaching 3, 4, and 5 years in the district are: \[ (3, 44,500), \quad (4, 46,000), \quad (5, 47,500) \]
The correct answer is: (3, 44,500), (4, 46,000), and (5, 47,500).