A man has $235.000 invested in three properties. One earns 12%, one 10%, and one 8%. His annual income from the properties is $22,500 and the amount invested at 8% is twice that invested at 12%. (a. How much is invested in each property? (b What is the annual income from each property?

Answer 1

If he has invested x@12%, y@10%, z@8% then
x+y+z = 235000
0.12x + 0.10y + 0.08z = 22500
z = 2x
Now solve as usual for x,y,z
then multiply each by its interest rate