A man has $210,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $20,100 and the amount invested at 8% is twice that invested at 12%. How much is invested in each property? at 12% 10% and 8% What is the annual income from each property?

Question

A man has $210,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $20,100 and the amount invested at 8% is twice that invested at 12%. How much is invested in each property? at 12% 10% and 8% What is the annual income from each property?
12% 10% and 8%

Reiny · Accepted Answer

invested at 12% ---- x
invested at 8% ----- 2x
invested at 10% -----210000- x - 2x = 210000-3x

.12x + .08(2x) + .10(210000-3x) = 20100
times 100
12x + 16x + 10(210000-3x) = 2010000
-2x = -90000
x = 45000

so 45000 at 12% ---> 5400
90000 at 8% -------> 7200
75000 at 10% ---- -> 7500 .... total is 20100

James · Answer

Thank You reiny do you think you can explan this one The total income from three investments was $2400. After 14 years, Investment I income has doubled, Investment II income has increased by 50% and Investment III went broke. If the income increase in Investment I equals the income increase in Investment II, and the total income has increased by $600, determine the total income in each investment. how much is invested at 1 2 and 3