A man built a house costing 9 times as much as the lot on which it was built. If the lot cost $5, 000 less than 1/6 the cost of the house, what was the cost of each?

Answer 1

If the house cost h, then the lot is h/9

h/6 - 5000 = h/9
h = 90,000

Answer 2

Can you show me how to work it out