A magnetic field has a magnitude of 1.2 10-3 T, and an electric field has a magnitude of 5.9 103 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 2.9 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.

Question

A magnetic field has a magnitude of 1.2  10-3 T, and an electric field has a magnitude of 5.9  103 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 2.9  106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.

Can you please clarify this for me. I have tried to work this problem but came up with incorrect answers each time. Please help!!!

bobpursley · Answer

Force=sqrt([Eq]^2 + [qvB]^2) Eq=5.9E3*1.8E-6=1.06E-3 N qvB=1.8E*-6*2.9E6*1.2E-3= Force= sqrt (11.2E-5 + 3.92E-5)=1.23E-2N That is worthy of rechecking.

Mary · Answer

Thank you so very much. It is only because of you and drwls that I am passing my physics class. Thanks again.