a long jumper travels 8.95 meters during a jump. he moves at 10.8 m/s when starts his leap. at what angle from the horizontal must he have been moving when he started his jump? you may need the double angle formula: 2 sin u cos u- sin (2u)

Answer 1

Horizontal distance covered = 8.95 m
= (Vo^2/g)*sin(2u)
Solve for the angle u.

Try deriving the formula. You will learn quite a bit in the process.