Question

A long jumper travels 8.95 meters during a jump. He moves at 10.8 m/s when starts his leap. At what angle from the horizontal must he have been moving when he started his jump? You may need the double-angle formula: 2 sin u cos u = sin (2u)

Answer 1

please can someone help?

Answer 2

The formula they are refering to is

X = (V^2/g) sin 2A

8.95 = 10.8^2/9.8 * sin@A = 11.9 sin2A

sin2A = 0.752

2A = 48.8 degrees or 131.2

A = 24.4 or 65.6 deg

The smaller angle is more likely because it allows the long jumper to get added distance by extending feet forward at landing

Answer 3

that is indded correct! can you help me on the other question i had too? its right above this post. it is either the electron or cannon question. thanks so much again!