A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?

7 answers

Assuming the digits are from 1 to 9, then the even is 2,4,6,8 and the odd are 1,3,5,7,9.

Prodd(ways/choices)=5/(2+5)
how do you do probability in decimals
ex. 3 and 4 chance of something, it would be .75 because 4 (100) x 3 of 100 is 75 so its .75!
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even
A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 1 and 2. What is the probability that the third digit is 3?
I'm sorry but i don't know the answer to your question, but i need help on this question:
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
I think the answer is 2/7