A lobster tank in a restaurant is 0.75 m long by 0.5 m wide by 50 cm deep. Taking the density of water to be 1000 kg/m^3, find the water forces
on the bottom of the tank: Force =
on each of the larger sides of the tank: Force =
on each of the smaller sides of the tank: Force =
(include units for each, and use g =9.8m/s^2
2 answers
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for the large wall, consider the weight of a slice of water of thickness dh. It is
0.75 * 1000 * 9.8 dh = 7350 dh
Now, the pressure is the weight * the depth, so to get the pressure on the whole wall, we need
p = ∫[0,0.5] 7350h dh = 918.75 N
similarly for the small wall
0.75 * 1000 * 9.8 dh = 7350 dh
Now, the pressure is the weight * the depth, so to get the pressure on the whole wall, we need
p = ∫[0,0.5] 7350h dh = 918.75 N
similarly for the small wall
2 answers