Break the weight of the sled into normal, and down the plane components.
Then, down the plane, you have a component of weight, opposiing it F and friction.
Now as F starts to move the sled upward, friction is now down the plane.
A loaded penguin sled weighing 60 N rests on a plane inclined at 20° to the horizontal. Between the sled and the plane the coefficient of static friction is 0.25, and the coefficient of kinetic friction is 0.18.
(a) What is the minimum magnitude of the force F, parallel to the plane, that will prevent the sled from slipping down the plane?
_________ N
(b) What is the minimum magnitude F that will start the sled moving up the plane?
__________ N
(c) What value of F is required to move the block up the plane at constant velocity?
_______ N
3 answers
4.5 N, 10.5, 23.0
a is wrong.