A load of 12 kg stretches 15 cm and a load of 30 kg stretches 18 cm. Find the natural (unstretched) length of the spring.

1 answer

K = (M2-M1)/(d2-d1) = (30-12)/(18-15) = 6 kg/cm .

d = (12kg/6kg) * 1cm = 2 cm.

L + 2 = 15, L = 13 cm.