"A line perpendicular to x + 3y = 5 passes through (1, -1). What is the

Question

equation of the line in standard form?"

Answer 1

You have a point (1,-1) and a slope 3
The point-slope form is

y-(-1) = 3(x-1)

Rearrange terms to get to standard form:

y+1 = 3x-3

-3x + y = -4