A line goes through points (2�ã3,-3) and (8�ã3,3). Find the equation of the line through these 2 points and the angle of incline (between the line and the x-axis).

Answer 1

The slope of your line is 6/(6√3) = 1/√3
Then, using the point (2√3,-3)

y+3 = (1/√3)(x-2√3)
cross-multiplying, expanding and then simplifying I got
x - (√3)y = 5√3 or if we multiply this by √3
(√3)x - 3y = 15

Answer 2

the slope of the line is equal to the tangent of the angle that the line makes with the x-axis
so tan(angle) = 1/√3
angle = 30º (from the ratios of the 30-60-90 triangle)