Asked by me
                A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).
            
            
        Answers
                    Answered by
            Reiny
            
    slope of the line going through the first two points
= (-7-9)/(-12-8) = -16/-20 = 4/5
so going through new point (-5,-15) with the same slope
y+15 = (4/5)(x+5)
do whatever you have to do further, but that is in
point-slope form
    
= (-7-9)/(-12-8) = -16/-20 = 4/5
so going through new point (-5,-15) with the same slope
y+15 = (4/5)(x+5)
do whatever you have to do further, but that is in
point-slope form
                    Answered by
            riri
            
    udk
    
                    Answered by
            Anonymous
            
    line passes through ( 1, -5 ) and ( -3, 7).
a.) Write an equation for the line point-slope form.
B, Rewrite the equation in slope-intercept form.
    
a.) Write an equation for the line point-slope form.
B, Rewrite the equation in slope-intercept form.
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