A light ray strikes a flat, L = 1.6 cm thick block (depth) of glass of refractive index 1.49 at an angle of 30 with the normal.

Calculate the lateral shift of the light ray, d.

there is a digram showing the light ray continuing at the same angle (30* to normal) until it exits the glass...so it has travelled down 1.6 cm.. once it leaves the angle decreases

is it correct to use

n1*sin(theta1)=n2*sin(theta2)

once i solve for sin(theta2)=opp/adj
sin(theta2)=d/1.6cm