Eastern distance = 250 km
northern distance = 600 km
looks like a right-angled triangle, and you want the hypotenuse
D^2 = 250^2 + 600^2
D = √...
= 650
base angle of that triangle :
tan^-1 θ = 600/250
θ = 67.4°
translate that into your "bearing"
A light aircraft with a cruising speed of 200km/h, flying in still air, first flew east for 1h 15 min, and then north for 3h. If the pilot now flies directly back to the home airfield, on what bearing should the pilot fly, and how long
will the flight take?
1 answer