A lead atom has a mass of 3.4 * 10 ^ - 22 * g How many lead atoms are in a cube of lead that has a volume of 4.50 cm^ 3 the density of lead is 11.3g/cm^ 3
2 answers
4.6 x 10^-22
really? a tiny fraction of one atom?
4.50cm^3 * 11.3g/cm^3 * 1atom/(3.4*10^-22 g)
= (4.5*11.3)/(3.4*10^-22)
= 1.50*10^23 atoms
4.50cm^3 * 11.3g/cm^3 * 1atom/(3.4*10^-22 g)
= (4.5*11.3)/(3.4*10^-22)
= 1.50*10^23 atoms