An atom of lead (Pb) having an atomic mass of 207 amu has an atomic number of 82. How many neutrons are present in this atom of lead?

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1 answer

125 neutrons.

To find the number of neutrons in an atom, you subtract the atomic number from the atomic mass. In this case, 207 (atomic mass) - 82 (atomic number) = 125 neutrons.
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