A lawn roller is pushed across a lawn by a force of 127 N along the direction of the handle, which is 22.5° above the horizontal. If 64.3 W of power is developed for 90.0 s, what distance is the roller pushed?

Answer 1

It is the hor. component of force that moves the roller:

Fh = 127*cos(22.5) = 117.3N.

P = FD / t = 64.3W,
117.3D / 90 = 64.3,
1.3D = 64.3,

D = 64.3 / 1.3 = 49.5m.