F cos24.2 * X = work done
= 66.1W*64s
= 4320 J
X = 4320/(Fcos24.2)
= 4320/99.42
= 43.5 m
A lawn roller is rolled across a lawn by a force
of 109 N along the direction of the handle,
which is 24.2� above the horizontal.
If the lawn roller develops 66.1 W of power
for 64 s, what distance is the roller pushed?
Answer in units of m.
1 answer
1 answer