A lawn mower handle makes an angle of 60° with the ground. A woman pushes on the handle with a force of 30 pounds. How much work is done in moving the lawn mower a distance of 75 feet on level ground?

Answer 1

The work done in moving the lawn mower a distance of 75 feet on level ground is 1,125 foot-pounds. This can be calculated by multiplying the force (30 pounds) by the distance (75 feet) and then multiplying the result by the cosine of the angle (60°): (30 pounds) * (75 feet) * cos(60°) = 1,125 foot-pounds.