A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 150 meters and the initial speed is 40 meters per second, what will its height be after 2 seconds rounded to the nearest tenth?

Answer 1

h = 150 + Vo*t - 4.9T^2.

h = 150 + 40*2 - 4.9*2^2,
h = 150 + 60.4 = 210.4m above ground.

h = 210.4 - 150 = 60.4m above the tower.