A large cylinder of helium had a small hole through which the helium escaped ata rate of 0.0064 mol/hr. How long would it take for 0.010 mol of CO to leak through a similar hole if it were at the same pressure?

Answer 1

The effusion rate will be inversely proportional to the square root of molecular mass

rate= .0064mol/hr( sqrt MolemassHe/molmassCO)

after you compute that, then time=.010/rate
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